1.90(t)=4.9t^2

Solution for 1.90(t)=4.9t^2 equation:

1.90(t)=4.9t^2

We move all terms to the left:

1.90(t)-(4.9t^2)=0

We get rid of parentheses

-4.9t^2+1.90t=0

a = -4.9; b = 1.90; c = 0;
Δ = b2-4ac
Δ = 1.902-4·(-4.9)·0
Δ = 3.61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.90)-\sqrt{3.61}}{2*-4.9}=\frac{-1.9-\sqrt{3.61}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.90)+\sqrt{3.61}}{2*-4.9}=\frac{-1.9+\sqrt{3.61}}{-9.8}
$